Is np.sqrt(-1) == np.emath.sqrt(-1)? Return the boolean result. (np.sqrt(-1) is NaN; np.emath.sqrt(-1) is 1j.)
np.sqrt(-1) == np.emath.sqrt(-1)
np.sqrt(-1)
np.emath.sqrt(-1)
1j
Sign in to write and run your own code.
solve(...)