Return a tuple (a, b, c) where (with numpy errors ignored): a = is np.array(0) / np.array(0) NaN?, b = int(np.array(0) // np.array(0)), c = float(np.array([np.nan]).astype(int).astype(float)[0]).
(a, b, c)
a
np.array(0) / np.array(0)
b
int(np.array(0) // np.array(0))
c
float(np.array([np.nan]).astype(int).astype(float)[0])
solve(...)